Question

3.4 x 10^23 atoms of potassium to grams

Answer 1

To solve this problem, we must take into account Avogadro's number. Avogadro's number tells us that in one mole of any substance there are 6.022x10^23 atoms. Applying this relationship we have that the moles of potassium (K) are:

`\begin{gathered} molK=givenatomsK*(1molK)/(6.022*10^(23)atoms) \\ \end{gathered}`
`\begin{gathered} molK=3.4*10^(23)atomsK*(1molK)/(6.022*10^(23)atoms) \\ molK=0.6molK \end{gathered}`

Now, to go from moles to grams, we must multiply the moles by the molar mass of potassium. The molar mass of potassium is 39.1g/mol. So, the grams of potassium will be:

`gK=givenmolK*(MolarMass,gK)/(1molK)`
`\begin{gathered} gK=0.6molK*(39.1gK)/(1molK) \\ gK=22.1gK \end{gathered}`

Answer: In 3.4x10^23 atoms of potassium there are 22.1 grams