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I need help with this practice problem solving This is the subject trigonometry

I need help with this practice problem solving This is the subject trigonometry-example-1

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Given the fucntion:

f(x) = tanx

Let's graph the function and input the correct values in the box.

• To find the y-intercept of the function, input 0 for x and solve:


\begin{gathered} f(0)=\tan 0 \\ \\ f(0)=0 \end{gathered}

Therefore, the y-intercept is:

(0, 0)

• The period of the function:

The fundamental period of a tangent function is π.

Now, let's find points on the graph:

Therefore, the points are:


\mleft(-(\pi)/(3),-√(3)\mright),\mleft(-(\pi)/(4),-1\mright),\mleft(0,0\mright),\mleft((\pi)/(4),1\mright),\mleft((\pi)/(3),√(3)\mright)

ANSWER:

The tangent function's period is π . The y-intercept of the function is (0, 0).

The points are:


(-(\pi)/(3),-\sqrt[]{3}),(-(\pi)/(4),-1),(0,0),((\pi)/(4),1),((\pi)/(3),\sqrt[]{3})

I need help with this practice problem solving This is the subject trigonometry-example-1
User Krishna Gupta
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