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1. Write the equation of a line perpendicular to thex 5and that passes through thepoint (6,-4).line y

User Pym
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1 Answer

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The line we want has a slope that is the negative reciprocal of the slope of the line

y = -(1/2)x - 5

The slope of this line is -1/2. So, the slope of its perpendicular lines is 2. Therefore, their equations have the form:

y = 2x + b

Now, to find b, we use the values of the coordinates of the point (6, -4) in that equation:

-4 = 2*6 + b

-4 = 12 + b

b = -4 - 12 = -16

Therefore, the equation is y = 2x - 16.

User Voldomazta
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