Question

PLEASE help I'll send a picture in later.

Answer 1

Given

Table of names

Procedure

Names end with an E

Gabe

Steve

The probability would be independent and equal to:

`\begin{gathered} (2)/(6)\cdot(2)/(6) \\ (4)/(36) \\ \\ (1)/(9) \end{gathered}`

The probability would be 1/9