Question

Oliver estimates the weight of his cat to be 16 pounds. The actual weight of his cat is 14.25 pounds. What is the percent error of Olver's estimate? Round the percent to the nearest tenth if necessary.

Answer 1

10.9%

Explanation:

14.25/16 = 0.890625

0.890625 * 100 = 89.0625

1 - 89.0625 = 10.9375%

Answer 2

The percent error is 10.9 %

EXPLANATION

The percent error is:

`\text{ \% error}=(|approx-exact|)/(exact)*100`

In this problem, the approximate value is 16 and the exact value is 14.25:

`\begin{gathered} \text{ \% error}=(|14.25-16|)/(16)*100 \\ \text{ \% error}=(1.75)/(16)*100 \\ \text{ \% error}=0.109375*100 \\ \text{ \% error}=10.9375\approx10.9\text{ \%} \end{gathered}`