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User Xstatic
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Given the following data

Base area of the cone = 6cm

Height of the cone = 9 cm

The volume of a cone is given as


\begin{gathered} V\text{ = }(1)/(3)\cdot\text{ }\pi\cdot r^2\cdot\text{ h} \\ \text{where }\pi\text{ = 3.14},\text{ r = 6cm , and h = 9cm} \\ V\text{ = }(1)/(3)\cdot\text{ 3.14 }\cdot6^2\cdot\text{ 9} \\ V\text{ = }(1)/(3)\text{ x 3.14 x 36 x 9} \\ V\text{ = }\frac{3.14\text{ x 36 x 9}}{3} \\ V\text{ = }(1017.36)/(3) \\ V=339.1cm^3 \end{gathered}

User Jeff Stewart
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