Recall that the numbers in a die are 1,2,3,4,5,6.

Hence the number of possible outcomes is 6.

We need a number less than 3. Let A be this event.

The favorable outcome is 2.

Since there are 1,2 less than 3 in a die.

Substitute n(A)=2 and n(S)=6, we get

Hence the required probability is 0.333.