Question

I need an quadratic equation with -3 and 6 for this assignment

Answer 1

If a quadratic equation has solutions

`x=a,x=b`

Then

`x-a=0\text{ and x-b=0}`

Furthermore, the quadratic can be written as

`\begin{gathered} y=(x-a)(x-b) \\ where,y=0 \end{gathered}`

Therefore,

`(x-a)(x-b)=0`

Given:

`a=-3,b=6`

Hence,

`\begin{gathered} (x--3)(x-6)=0 \\ (x+3)(x-6)=0 \end{gathered}`

Simplify

`\begin{gathered} x(x-6)+3(x-6)=0 \\ x^2-6x+3x-18=0 \\ x^2-3x-18=0 \end{gathered}`

Hence, the quadratic equation is

`x^(2)-3x-18=0`