We will have that the lateral area will be the following:
*First, we can see that if we were to cut a straight vertical line and unfold the label, we would get a rectangle, thus the surface area of the label will be given by:
![S_A=h\cdot C](https://img.qammunity.org/2023/formulas/mathematics/high-school/58pw4hx8lec2d9b1rkfaltuba5pdgit9db.png)
Here h is the height of the label and C is the circumference of the base, that is:
![S_A=h\cdot2\pi r](https://img.qammunity.org/2023/formulas/mathematics/high-school/vw1gpiexo6xmkr00gyj78zn63nrm8wwwyx.png)
Now, we determine the radius of the base, that is:
![r=(2.6)/(2)\Rightarrow r=1.3](https://img.qammunity.org/2023/formulas/mathematics/high-school/j5ljydl4mvnoz0awkk8pp7b21wx5t192k3.png)
Now, we replace the values and solve for the surface area:
![\Rightarrow S_A=(4)\cdot(2)\pi(1.3)\Rightarrow S_A\approx32.7](https://img.qammunity.org/2023/formulas/mathematics/high-school/bgw0lwgeqwdc1377rg99i0q74lit4lulik.png)
So, the surface area of the label on the can is approximately 32.7 squared inches.