Question

Given ABC below, with m B=25°, a = 9, and c = 16, find the area of the triangle.

Answer 1

It is given that the sides of the triangle are a =9 and c=16 . The angle is given mB=25 degree.

The area of triangle is determined as

`A=(1)/(2)a* c*\sin B`
`A=(1)/(2)*9*16*\sin 25=72\sin 25^(\circ)`
`A=30.428sq\mathrm{}\text{unit}`

Thus the area of triangle is 30.428 sq.unit.