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The air in a tire pump has a volume of 1.5 L at a temperature of 5 ℃. If the temperature is increased to 25 ℃ and the pressure remains constant, what is the new volume of the tire pump

User Oliverguenther
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1 Answer

16 votes
16 votes

Answer:

Step-by-step explanation:

5 C = 278 K

25 C = 298 K

V1 / T1 = V2 / T2

1.5L / 278 K = V2 / 298 K

V2 = (1.5L * 298) / 278

V2 = 1.61 L

User Bartek Tatkowski
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