Answer:
The equation of the line is;
![y=-(3)/(4)x+5](https://img.qammunity.org/2023/formulas/mathematics/college/cwqw2sskm6xcozy5x5r61rtegxt5fwlk0m.png)
Step-by-step explanation:
Given that the line has a slope of;
![m=-(3)/(4)](https://img.qammunity.org/2023/formulas/mathematics/high-school/plhnx6ksfv6tpt4vg4lz92ae920qasecvj.png)
And passes through the point;
![(8,-1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/3ie77wquiatn75dnh37trlfq18o9bnvyz6.png)
Applying the point-slope equation of straight line;
![y-y_1=m(x-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/csobd57zth7rh9k4hz9amldzpq2owf0z4j.png)
substituting the given values and solving;
![\begin{gathered} y-(-1)=-(3)/(4)(x-8) \\ y+1=-(3)/(4)x-(3)/(4)(-8) \\ y+1=-(3)/(4)x+6 \\ y=-(3)/(4)x+6-1 \\ y=-(3)/(4)x+5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/llx03pj30lchobpsm0on62ykwvg9lly8rh.png)
Therefore, the equation of the line is;
![y=-(3)/(4)x+5](https://img.qammunity.org/2023/formulas/mathematics/college/cwqw2sskm6xcozy5x5r61rtegxt5fwlk0m.png)