Question

Which answer shows how to solve the given equation using the quadratic formula? 22 - 3. - 4= 0 3+, 22-4(2)(-4) 2(2) -(-3)=1/(-3)2-4(2)(-4) 2(2) 4+/(-3) -4(2)(-4) 2 3+1/32-4(-3)(-4) 2(2)

Answer 1

hello

the question here is a given quadratic equation and we're required to use quadratic formula to solve it.

`2x^2-3x-4=0`

now, to solve this, let's bring out quadratic formula first

`x=-b\pm\frac{\sqrt[]{b^2-4ac}}{2a}`

now from our equation given, we can easily identify a, b and c.

`\begin{gathered} 2x^2-3x-4=0 \\ a=2 \\ b=-3 \\ c=-4 \end{gathered}`

next we plug in the variables into the equation and solve