Question

2. Oxygen gas is collected at a pressure of 123 kPa in a container which has a volumeof 10.0 L. What temperature must be maintained on 0.654 moles of this gas in order tomaintain this pressure? Express the temperature in Kelvin.

Answer 1

T = 226.21 K

Step-by-step explanation

Given:

Pressure = 123 kPa

Volume = 10.0 L

number of moles = 0.654 moles

We know R = 8.314 L kPa/mol k.

Required: Temperature

Solution:

Pv = nRT

T = PV/nR

T = (123 kPa x 10.0 L)/(0.654 mol x 8.314 L kPa/mol k)

T = 226.21 K