229k views
4 votes
Directions: Solve the following problems. Show your solutions.2. A circuit has three resistors connected in parallel. Their resistances are 11 Ω, 17 Ω, and 12 Ω as shown on the figure below. Find for: a. Voltage in R1 (V1)b. Voltage in R2 (V2)c. Voltage in R3 (V3)d. Total Resistance (RT)e. Total Current (IT)f. Current in R1 (I1)g. Current in R2 (I2)h. Current in R3 (I3)

Directions: Solve the following problems. Show your solutions.2. A circuit has three-example-1

1 Answer

4 votes

Since the resistances are in parallel, the voltage in each one is the same, so:

a. V1 = 60 V

b. V2 = 60 V

c. V3 = 60 V

d.

The total resistance of parallel resistances can be calculated with the formula below:


\begin{gathered} (1)/(RT)=(1)/(R1)+(1)/(R2)+(1)/(R3)\\ \\ RT=(R1\cdot R2\cdot R3)/(R1R2+R2R3+R1R3)\\ \\ RT=\frac{11\cdot17\cdot12}{11\cdot17+17\operatorname{\cdot}12+11\operatorname{\cdot}12}\\ \\ RT=(2244)/(523)\\ \\ RT=4.29\text{ ohms} \end{gathered}

e.

The total current is given by the voltage divided by the total resistance:


IT=(V)/(RT)=(60)/(4.29)=13.99\text{ A}

The current in each resistor is given by the voltage divided by the resistance:

f.


I1=(V1)/(R1)=(60)/(11)=5.45\text{ A}

g.


I2=(V2)/(R2)=(60)/(17)=3.53\text{ A}

h.


I3=(V3)/(R3)=(60)/(12)=5\text{ A}

User Hooligancat
by
5.5k points