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-21 < f (x) < 0 , where f (x) = - 2x- 5

1 Answer

2 votes

We can solve this using the next property:

If a

Replace f (x) = - 2x- 5 ​, then:

-21 < f (x) < 0

-21 < -2x-5 < 0

Solve -21 < -2x-5 and -2x-5 < 0

Therefore:

-21 < -2x-5

Add both sides 5

-21+5 < -2x-5 +5

-16 < -2x

(-1)-16 < (-1)(-2x)

16>2x

x<16/2

x<8

and

-2x-5 < 0

Add both sides 5

-2x-5 +5 < 0+5

-2x<5

(-1)-2x < (-1)5

2x > -5

x > -5/2

Hence, the resulting interval is:

-5/2 < x < 8

User Ricardo Sanchez
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