Question

Two parallel wires carry currents of 20 A and 10 A, respectively, in the opposite direction and have a length of 5 m each. Determine the force between the wires if the distance between the wires is 1.0 cm.0.010 N, attraction0.010 N, repulsion0.020 N, attraction0.020 N, repulsion

Answer 1

Given:

The currents, I₁=20 A

I₂=10 A

The length of the wires, L=5 m

The distance between two wires, d=1.0 cm=0.01 m

To find:

The magnetic force between the wires.

Step-by-step explanation:

As the wires are conducting the current in opposite directions, the nature of the force between the wires is repulsive.

The magnitude of the force between two wires is given by,

`F=(\mu_0I_1I_2L)/(2\pi d)`

Where μ₀=4π×10⁻⁷ H/m is the permeability of free space.

On substituting the known values,

`\begin{gathered} F=(4\pi*10^(-7)*20*10*5)/(2\pi*1*10^(-2)) \\ =0.02\text{ N} \end{gathered}`

Final answer:

The magnetic force between wires is 0.020 N, repulsive.