Given the equation 4x-8=12 you need to clear the value of x.
First step is to leave the value of x in one side of the equation and the integers in the other side, to do so you have to add 8 to both sides of the equation
![\begin{gathered} 4x-8=12 \\ 4x-8+8=12+8 \\ 4x=20 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/61sd43cnkqn9b0i2tcqf0ifmzel7gp6lgd.png)
Next you have to divide both terms of the equation by 4 to get the value of x
![\begin{gathered} 4x=20 \\ (4x)/(4)=(20)/(4) \\ x=5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/y4eerunwe2wzidp38zkwcs7aeacdcct7s9.png)
The value of x=5