Given data:
Total displacement of the car;

Speed limit;

The angle of street from horizontal;

Coefficient of static friction;

Coefficient of kinetic friction;

Mass of the car;

Weight of the man;

The kinetic friction force is given as,

Here, m is the mass of the man and g is the acceleration due to gravity.
The acceleration of the car driving up a steep hill is given as,

Substituting all known values,

The velocity of the car is given as,

Here, v is the final velocity (v=0, as the car stops), and u is the initial velocity.
The initial velocity of the car is given as,
![u=\sqrt[]{v^2+2as}](https://img.qammunity.org/2023/formulas/physics/college/z3861el3wx1nvk4pcoz7ur2dfodr6pv81u.png)
Substituting all known values,
![\begin{gathered} u=\sqrt[]{0^2+2*(30.92\text{ ft/s}^2)*(50\text{ ft})} \\ \approx55.61\text{ ft/s} \\ \approx37.91\text{ mph} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/hp4cg6hc3rrxb47g1zybl87ypm8o9nvl1r.png)
Therefore, your speed is greater than the speed limit. Thus, you can not fight the ticket in the court.