Question

Density of gasses lawA sample of gas with a density of 0.066 g/l at 32 C and a pressure of 0.95 atm. Find the density of the gas at STP

Answer 1

`0.078\text{ g/l}`

Step-by-step explanation:

Here, we want to calculate the density of the gas at STP

We use a modification of the general gas law as follows

Mathematically:

`(P_1)/(D_1* T_1)\text{ = }(P_2)/(D_2* T_2)`

where:

P1 is the initial pressure which is 0.95 atm

D1 is the initial density which is 0.066 g/l

T1 is the initial temperature in Kelvin (we add the temperature in Celsius with 273 K : 32 + 273 = 305 K)

P2 is the pressure at STP which is 1 atm

D2 is the density that we want to calculate

T2 is the temperature at STP which is 273 K

Substituting the values, we have it that:

`\begin{gathered} (0.95)/(0.066*305)\text{ = }(1)/(D_2*273) \\ \\ D_2\text{ = }(0.066*305)/(0.95*273)\text{ = 0.078 g/l} \end{gathered}`