Question

if AC equals x + 3 and DB equals 3x - 19 find a CFA E equals 3x + 3 + E C equals 5x - 15 find a c d equals 50x - 7 + 80 equals 4x + 9 find DB

Answer 1

2) If DB = 27 the we can replace that:

`27=3x-19`

and we can solve for x

`\begin{gathered} 3x=27-19 \\ 3x=8 \\ x=(8)/(3) \end{gathered}`

now we can replace x in the equation for AC:

`\begin{gathered} AC=x+3 \\ AC=(8)/(3)+3 \\ AC=(8)/(3)+(9)/(3) \\ AC=(17)/(3) \end{gathered}`

3) we have that:

`\begin{gathered} AE=3x+3 \\ EC=5x-15 \end{gathered}`

So the segment AC will be the sum of the segments:

`\begin{gathered} AC=AE+EC \\ AC=3x+3+5x-15 \\ AC=8x-12 \end{gathered}`

and we also know that

`\begin{gathered} x=(8)/(3) \\ \text{then} \\ AC=(64)/(3)-(36)/(3) \\ AC=(28)/(3) \end{gathered}`

3) we have that:

`\begin{gathered} DE=6x-7 \\ AE=4x+6 \end{gathered}`