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How long will it take for an investment of 2900 dollars to grow to 6800 dollars, if the nominal rate of interest is 4.2 percent compounded quarterly? FV = PV(1 + r/n)^ntAnswer = ____years. (Be sure to give 4 decimal places of accuracy.)

User Geotob
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ANSWER :

The answer is 20.3971 years

EXPLANATION :

The compounding interest formula is :


FV=PV(1+(r)/(n))^(nt)

where :

FV = future value ($6800)

PV = present value ($2900)

r = rate of interest (4.2% or 0.042)

n = number of compounding in a year (4 : compounded quarterly)

t = time in years

Using the formula above :


6800=2900(1+(0.042)/(4))^(4t)

Solve for t :


\begin{gathered} (6800)/(2900)=(1.0105)^(4t) \\ \text{ take ln of both sides :} \\ \ln((6800)/(2900))=\ln(1.0105)^(4t) \\ \operatorname{\ln}((6800)/(2900))=4t\operatorname{\ln}(1.0105) \\ 4t=(\ln((6800)/(2900)))/(\ln(1.0105)) \\ t=(\ln((6800)/(2900)))/(4\ln(1.0105)) \\ t=20.3971 \end{gathered}

User Benjamin Merchin
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