The equation for the total amount after compounded interest is as follows:
![A=P(1+(r)/(n))^(nt)^{}](https://img.qammunity.org/2023/formulas/mathematics/college/rf489c8offc95xe6tn1zekcifa9noqs88i.png)
Where A is the final amount, P is the initial amount, r is the annual interest, n is how many times per year the interest is compounded and t is the time in years.
Since the interest is compounded annually, it is compounded only once per year, so
![n=1](https://img.qammunity.org/2023/formulas/mathematics/college/nim43b1yql364u1zglrtmebqdzuoriy01t.png)
The other values are:
![\begin{gathered} P=4400 \\ r=3.2\%=0.032 \\ t=12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/dfwlv6ppbdd6oml3d53qfuq39gxefw7gdf.png)
So, substituteing these into the equation, we have:
![\begin{gathered} A=4400(1+(0.032)/(1))^(1\cdot12) \\ A=4400(1+0.032)^(12) \\ A=4400(1.032)^(12) \\ A=4400\cdot1.4593\ldots \\ A=6421.0942\ldots\approx6421 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/2oxi6nemx48zhb96qt6zbrfmsm8wt2luzd.png)
So, she will have approximately $6421.