Question

A scale drawing of a rectangular park is 4 inches wide and 8 inches long. The actual park is 320 yards long. What is the perimeter of the actual park, in square yards?

Answer 1

Given:

• Width of scale drawing = 4 inches

,

• Length of scale drawing = 8 inches

,

• Length of actual park = 320 yards

Let's find the perimeter of the actual park.

Let's first find the width of the actual park.

To find the width of the actual park, we have:

`\begin{gathered} \text{ width of actual = }\frac{\text{ length of actual}}{\text{ length of scale}}*\text{ width of scale} \\ \\ \\ \text{ width of actual = }(320)/(8)*4 \\ \\ \text{ width of actual = 40 * 4 = 160 yards} \end{gathered}`

The width of the actual park is 160 yards.

Now, to find the perimeter of the actual park, apply the formula do perimeter of a rectangle:

P = 2(L + W)

Where:

P is the perimeter

L is the length = 320 yards

W is the width = 160 yards

Thus, we have:

P = 2(320 + 160)

P = 2(480)

P = 960 yards

Therefore, the perimeter of the actual park is 960 yards.

ANSWER:

960 yards