3.
We need to find the equation of the line which:
• crosses the y-axis at -5
,
• crosses the x-axis at 2
The y-axis cutting point is (0,-5)
The x-axis cutting point is (2,0)
The equation of line is:
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
Where m is the slope and b is the y-axis cutting point
m is given by:
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/78uaqhwt0aws3qfwxigaftpihnmb1gzxtp.png)
Where
y_2 = 0
y_1 = -5
x_2 = 2
x_1 = 0
So, slope is:
![m=(y_2-y_1)/(x_2-x_1)=(0--5)/(2-0)=(0+5)/(2)=(5)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/rpirn28owrvdgh1f28sypiplguvv2021ox.png)
We got m, we also know b.
The y cutting point is -5, so b = -5
The equation is:
![y=(5)/(2)x-5](https://img.qammunity.org/2023/formulas/mathematics/college/mrszg3imff2h49ophjgek5e6do2tgapyo3.png)
The graph would look like:
More clear version: