Question

Not a timed or graded assignment. Need a quick answer tho. Thank you

Answer 1

Difference of squares

`8x-7`

Explanation:

We have the following quotient:

`(64x^2-49)/(8x+7)`

We factor, knowing that the numerator is a difference of squares, therefore:

`\begin{gathered} a^2-b^2=(a+b)(a-b) \\ \text{ in this case} \\ a=8x \\ b=7 \\ 64x^2-49=(8x+7)(8x-7) \\ \text{ Replacing:} \\ ((8x+7)(8x-7))/(8x+7)=8x-7 \end{gathered}`