Question

Hi, I need help with classwork. I am only really great at geometry, so I would appreciate it if someone lend a hand, thank you.

Answer 1

1: x=16

2: I'm not sure

3: I'm not sure

4a: Yes (Diagonals Bisect)

4b: Yes (Opposite Angles Congruent)

4c: Yes (Opposite Sides Congruent and Parallel)

4d: Yes (Opposite Sides Parallel/Opposite Angles Congruent)

5: (7,9)

6a: AB=4/3 CD= 4/3

6b: AB=5 CD= 10

6c: No, it doesn't any of the characteristics of a parallelogram

Step-by-step explanation:

1: Consecutive angles are supplementary because it is a proven parallelogram

`3x+5+9x-17=180\\12x-12=180\\12x=192\\x=16`

2: I haven't learned this yet

3: I haven't learned this yet

4a: See Above

4b: See Above

4c: See Above

4d: See Above

5:
`mp(x)= (x_(1)+x_(2))/(2) \\ mp(y)= (y_(1)+y_(2))/(2) \\`
`4=(1+x)/(2) \\8=1+x\\x=7`
`6=(3+y)/(2)\\12=3+y\\y=9`

6a:
`(7-3)/(0-(-3))=(4)/(3) \\(-1-7)/(2-8)=(-8)/(-6) =(4)/(3)`

6b:
`d=\sqrt{(x_(2)-x_(1))^(2)+ (y_(2)-y_(1))^(2)}\\d=\sqrt{(0-(-3))^(2)+ (7-3)^(2)}\\d=\sqrt{(3)^(2)+ (4)^(2)}\\d=√(9+ 16)\\d=√(25)\\d(AB)=5`
`d=\sqrt{(x_(2)-x_(1))^(2)+ (y_(2)-y_(1))^(2)}\\d=\sqrt{(-1-7)^(2)+ (2-8)^(2)}\\d=\sqrt{(-8)^(2)+ (-6)^(2)}\\d=√(64+ 36)\\d=√(100)\\d(AB)=10`

6c: See Above