Question

Given the special right triangle, find the value of x and y. Express your answer in simplest radical form.

Answer 1

`\begin{gathered} To\text{ calculate x} \\ \sin \text{ (60)=}(x)/(10) \\ x=10\cdot\sin \text{ (60)} \\ x=10\cdot\frac{\sqrt[]{3}}{2}=8.66\approx8.7 \\ x=8.7 \\ The\text{ value of x is 8}.7 \\ \\ To\text{ calculate y} \\ \cos (60)=(y)/(10) \\ y=10\cdot\cos (60) \\ y\text{ = 10}\cdot(1)/(2) \\ y=5 \\ \text{The value of y is 5} \end{gathered}`