Question

What is the specific heat capacity of methanol (C) if it takes 7,490 joules of energy to heat 50.0 grams from 10.0 0C to 80.0 0C?

Answer 1

`c=2.14J\text{/g}^0C`

Explanations

The formula for calculating the amount of heat energy absorbed is given as:

`Q=mc\triangle t`

Given the following

• mass m = 50.0g

,

• Heat energy Q = 7490 Joules

,

• change in temperature = 80 -10= 70 degrees celsius

Substitute

`\begin{gathered} 7490=50* c*70 \\ c=(7490)/(3500) \\ c=2.14J\text{/}g^oC \end{gathered}`

Hence the specific heat capacity of methanol is 2.14J/gC