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Henry had a batting average of 0.341 last season (out of 1000 at-bats, he had 341 hits). Given that thisbatting average will stay the same this year, answer the following questions,What is the probabilitythat his first hit willoccur within his first 5at-bats? Answer choice. 0.654. 0.765. 0.821. 0.876

User Toshiaki
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The probability of a successful batting is 0.341; we need to find the probability of at least 1 hit within the first 5 at-bats; thus,


P(Hit)=1-P(NoHit)

Therefore, we need to calculate the probability of not hitting the ball within the first 5 at-bats.

The binomial distribution states that


\begin{gathered} P(X=k)=(nBinomialk)p^k(1-p)^(n-k) \\ n\rightarrow\text{ total number of trials} \\ k\rightarrow\text{ number of successful trials} \\ p\rightarrow\text{ probability of a successful trial} \end{gathered}

Thus, in our case,


P(k=0)=(5Binomial0)(0.341)^0(0.659)^5=1*1*0.124287...

Then,


P(Hit)=1-0.124287...\approx0.876

Therefore, the answer is 0.876

User Pragma
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