Let:
x = Number of months
y1 = Total cost for Club A
y2 = Total cost for Club B
a = Fee of Club A per month
b = Fee of Club B per month
c = Initial fee of Club A
d = Initial fee of Club B
so:
![\begin{gathered} y1=ax+c \\ y1=25x+20 \\ -------- \\ y2=bx+d \\ y2=24x+25 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/o6y4xu5fo232etwakdaygo1vq45e9wmge3.png)
So, the total cost will be the same for:
![\begin{gathered} y1=y2 \\ 25x+20=24x+25 \\ solve_{\text{ }}for_{\text{ }}x\colon \\ 25x-24x=25-20 \\ x=5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ro7hjdblq1tgw9a615zkizhq9ody9en3mt.png)
The cost will be the same for the month number 5. And the total cost will be:
![\begin{gathered} y1(5)=25(5)+20=145 \\ y2(5)=24(5)+25=145 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/72x0xxkue2csveau50z7qe0jbpb3444wvc.png)
$145