1) In this question let's calculate the sin(θ) and cos(θ)
Given that
![\begin{gathered} \text{If }\sin (\theta)=(5\pi)/(4) \\ \sin (\theta)\text{ }\Rightarrow\sin ((5\pi)/(4))\text{ }=-\frac{\sqrt[]{2}}{2} \\ \cos ((5\pi)/(4))=-\frac{\sqrt[]{2}}{2} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qdfve902ag32vyopov2t239ul3rmg4wg1l.png)
2) In this question, we're calculating the value of the sine and the cosine in radians.
We must remember that 5π/4 ⇒ to 225º, and that it's in the Quadrant III
If we subtract
225 -180 =45 So the sine of 5π/4 is -√2/2 and the cosine (5π/4 ) = -√2/2
2.3) The sign of the Quadrant
Since 225º is in Quadrant III both results are negative ones.