Question

Find two consecutive numbers whose sum is 201.

smaller number =

larger number =

Answer 1

100 and 101

Explanation:

Hi there!

Let x be equal to the smaller number.

Let x + 1 be equal to the larger number, which is consecutive to the smaller number.

We are given that the sum of the two numbers is 201:

`x+(x+1)=201\\x+x+1=201\\2x+1=201\\2x=200\\x=100`

Therefore, the smaller number is 100. Because the larger number is x + 1, it is 101.

I hope this helps!