Question

suppose there are two types of tickets to a show . advance and same day. advance tickets cost $15 and same day tickets cost 30. for one more performance there are 55 tickets sold in all and the total amount paid for them was 1275. how many tickets of each typer were sold?

Answer 1

Advanced tickets(x): $15

Same day tickets(y) : $30

For one more performance there are 55 tickets sold

x+ y= 55 (a)

The total amount paid for them was 1275

15x+30y= 1275 (b)

System of equations:

x+y= 55 (a)

15x+30y = 1275 (b)

Solve for x in (a)

x=55-y

Replace x on (b)

15(55-y)+30y = 1275

82