Question

Event A, Event B, and Event Care provided. Event A and Event B aremutually exclusive. Event A and Event C are not mutually exclusive.P(A) = 0.45P(B) = 0.30P(C) = 0.25What is the probability of the union of A and B?

Answer 1

Given data:

The probability of A is P(A)=0.45.

The probability of B is P(B)=0.30.

The expression for the mutually exclusive events is,

`P(A\cap B)=0`

The expression for the probability of A union B is,

`\begin{gathered} P(A\cup B)=P(A)+P(B)-P(A\cap B) \\ =0.45+0.30-0 \\ =0.75 \end{gathered}`

Thus, the probability of (AUB) is 0.75.