Question

What is the area in square feet ( of the rectangle) of 4 3/4 feet and 6 4/5 feet

Answer 1

Recall the area of a rectangle is determined by the formula

`\begin{gathered} A_{\text{rectangle}}=lw \\ \text{where} \\ l\text{ and }w\text{ are the dimensions of the rectangle} \end{gathered}`

Given the following

w = 4 3/4 ft

l = 6 4/5 ft

Convert the following given into improper fraction first

`\begin{gathered} w=4(3)/(4)\text{ ft}\Longrightarrow w=(19)/(4)\text{ ft} \\ l=6(4)/(5)\text{ ft }\Longrightarrow l=(34)/(5)\text{ ft} \end{gathered}`

Next, substitute those values to the given formula for solving the area of the rectangle

`\begin{gathered} A=lw \\ A=(34)/(5)\text{ ft}\cdot(19)/(4)\text{ft} \\ A=(646)/(20)\text{ ft}^2 \\ \text{Convert the final answer back into mixed fractions} \\ A=(646)/(20)\text{ ft}^2\Longrightarrow A=32(3)/(10)\text{ ft}^2 \\ \\ \text{Therefore, the area of the rectangle is} \\ 32(3)/(10)\text{ ft}^2 \end{gathered}`