Question

Not sure on how to do this. Would really like some help.

Answer 1

Given:

`\cos60^(\circ)`

To find:

The value

Step-by-step explanation:

We know that,

`\cos\theta=\sin(90-\theta)`

So, we write,

`\begin{gathered} \cos60^(\circ)=\sin(90-60) \\ =\sin30^(\circ) \\ =(1)/(2) \end{gathered}`

Final answer:

`\cos60^(\circ)=(1)/(2)`