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What is the mass of 12 m3 of methylated spirit whose relative density is 0.8 ? ( Hint the density of water = 1000 kgm-3 ) A. 9600 kg B.9400 kg C. 8600 kg

1 Answer

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ANSWER

A. 9600 kg

Step-by-step explanation

Given:

• The volume of the substance, V = 12m³

,

• The relative density of the substance, 0.8

,

• The density of water, 1000 kg/m³

Unknown:

• The mass of the substance, m

The relative density of a substance is defined as,


\rho_(relative)=(\rho_(substance))/(\rho_(water))

And the density of a substance is,


\rho=(m)/(V)

Let's solve the first formula for the density of the substance,


\rho_(substance)=\rho_(relative)\cdot\rho_(water)=0.8\cdot1000\operatorname{kg}/m^3=800\operatorname{kg}/m^3

Then, solve the second formula for m,


m=\rho\cdot V=800\operatorname{kg}/m^3\cdot12m^3=9600\operatorname{kg}

Hence, the mass of this substance is 9600 kg

User Dan Temkin
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