1 Answer

Dan Temkin · Answer 1 · 2023-04-10T04:27:27+0000

ANSWER

A. 9600 kg

Step-by-step explanation

Given:

• The volume of the substance, V = 12m³

,

• The relative density of the substance, 0.8

,

• The density of water, 1000 kg/m³

Unknown:

• The mass of the substance, m

The relative density of a substance is defined as,

$\rho_(relative)=(\rho_(substance))/(\rho_(water))$

And the density of a substance is,

$\rho=(m)/(V)$

Let's solve the first formula for the density of the substance,

$\rho_(substance)=\rho_(relative)\cdot\rho_(water)=0.8\cdot1000\operatorname{kg}/m^3=800\operatorname{kg}/m^3$

Then, solve the second formula for m,

$m=\rho\cdot V=800\operatorname{kg}/m^3\cdot12m^3=9600\operatorname{kg}$

Hence, the mass of this substance is 9600 kg

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