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11) In the reaction 2SO2(g) + O2(g) → 2SO3(g), how many moles of O2 are needed to produce 8.46 moles of SO3?

User Azquelt
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To solve this question, we need to look at the stoichiometric ratio between oxygen and SO₃, which in this case is 1:2

So 1 mole of O2 produces 2 moles of SO3.

Now we can use the rule of 3:

1 mole O2 --- 2 mole SO3

x mole O2 --- 8.46 moles SO3

2x = 1 x 8.46

x = 8.46/2

x = 4.23

Answer: 4.23 moles of O2

User Hilen
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