Given the points:
(x1, y1) ==> (2, -2)
(x2, y2) ==> (0, -1)
To find the linear equation, use the form:
y = mx + b
where m is the slope.
To find the slope, use the formula below:
![m=(y2-y1)/(x2-x1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/wt3vklmulg2853jxzclws9uvfaplhmpgv7.png)
Thus, we have the slope as:
![m=(-1-(-2))/(0-2)=(-1+2)/(0-2)=(1)/(-2)=-(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/4hmhvqq80ais5645sewtn456t4oambd4hh.png)
Input 2 for x, -2 for y, and -1/2 for b to find b.
![\begin{gathered} -2=-(1)/(2)(2)+b \\ \\ -2=-1+b \\ \\ -2+1=b \\ \\ -1=b \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4revmpayifq05pt8f3cxkyiz21pfxs4827.png)
Therefore, the linear equation is:
![y=-(1)/(2)x-1](https://img.qammunity.org/2023/formulas/mathematics/college/viv4u3f0lx3t1j62i43xgjpmz2wayi5111.png)
ANSWER:
![y=-(1)/(2)x-1](https://img.qammunity.org/2023/formulas/mathematics/college/viv4u3f0lx3t1j62i43xgjpmz2wayi5111.png)