The company's sign has two(2) congruent trapezoids and two(2) congruent right angled triangle.
The area of the figure is:
![A_{\text{figure}}=2A_{\text{trapezoid}}+2A_{\text{triangle}}](https://img.qammunity.org/2023/formulas/mathematics/college/5z3eycho6pa075arrglnuron5qxlrjq1oy.png)
The area of a trapezoid is given by the formula:
![\begin{gathered} A_{\text{trapezoid}}=(1)/(2)(a+b)h \\ \text{where a and b are opposite sides of the trapezoid} \\ h\text{ is the height} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/cb9rru2u6dizwzcm72rsjzf642kn350rwh.png)
Thus, we have:
![\begin{gathered} A_{\text{trapezoid}}=(1)/(2)(1(1)/(2)+3)2 \\ A_{\text{trapezoid}}=(1)/(2)(1.5+3)2 \\ A_{\text{trapezoid}}=(1)/(2)*4.5*2=4.5m^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4dgw5zbdti2sd3b1hff7l8s80e7wks3bwc.png)
Area of a triangle is given by the formula:
![A_{\text{triangle}}=(1)/(2)* base* height](https://img.qammunity.org/2023/formulas/mathematics/college/wti0s3mb0q4yl9q6tv1kyylhhdzl5a8tda.png)
Thus, we have:
![\begin{gathered} A_{\text{triangle}}=(1)/(2)*2*1(1)/(2) \\ A_{\text{triangle}}=(1)/(2)*2*1.5=1.5m^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ci3wejcpgsjgmc4g7p5s7vnufzev3yry19.png)
Hence, the area of the company's sign is:
![\begin{gathered} A=(2*4.5)+(2*1.5) \\ A=9+3=12m^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7vgodzy6shnca8qqcok7nzlyaqztr9xooi.png)