Question

There are two boxes containing only red and purple pens.Box A has 12 purple pens and 3 red pens.Box B has 14 purple pens and 6 red pens.A pen is randomly chosen from each box.List these events from least likely to most likely.Event 1: choosing a purple or red pen from Box A.Event 2: choosing a green pen from Box B.Event 3: choosing a purple pen from Box B.Event 4: choosing a purple pen from Box A.Least likelyMost likelyEventEventEventEvent

Answer 1

Event 1: choosing a purple or red pen from Box A

All pens are purple or red so the probability is:

`P=(12+3)/(15)=(15)/(15)=1`

Event 2: choosing a green pen from Box B

We don't have green pens, so the probability is 0.

Event 3: choosing a purple pen from Box B

We have 14 purple pens and 20 total pens, so:

`P=(14)/(20)=(7)/(10)=0.7`

Event 4: choosing a purple pen from Box A

We have 12 purple pens and 15 total pens, therefore:

`P=(12)/(15)=(4)/(5)=0.8`

Listing from least likely to most likely, we have:

event 2 < event 3 < event 4 < event 1

Answer:

Event 2, Event 3, Event 4, Event 1