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5 votes
1+2 |x-1| less than or equal to 9

1 Answer

3 votes

SOLUTION

The question is


1+2|x-1|\leq9

Now let's solve. This becomes


\begin{gathered} 1+2|x-1|\leq9 \\ 2|x-1|\leq9-1 \\ 2|x-1|\leq8 \\ \\ \text{dividing both sides by x we have} \\ \\ |x-1|\leq4 \end{gathered}

This becomes


\begin{gathered} x-1\leq4 \\ or \\ x-1\ge4 \end{gathered}

So we have our x as


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User Tearvisus
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