Question

How to solve 2x^2-3x-1=0

Answer 1

`\begin{gathered} x_1=(-9+√(17))/(2) \\ x_2=(-9-√(17))/(2) \end{gathered}`

Step-by-step explanation

`2x^2-3x-1=0`

Step 1

remember the quadratic formula.

if you have the equation

`ax^2+bx+c=0`

the value for x is

`x=(-b^2+√(b^2)-4ac)/(2a)`

Step 2

let

`ax^2+bx+c=2x^2-3x-1`

a=2

b=-3

c=-1

Step 3

replace