Question

Find an equation of the line parallel to the graph of y = -5x-3 that passes throughthe point of (3,2). Write your equation in slope-intercept form.

Answer 1

Parallel lines has the same slope. In our case, the slope is -5. Then, the searched line has the form:

`y=-5x+b`

where b is the y-intercept.

We can find b by substituting the given point (3,2) into the las equation. Then, we have

`2=-5(3)+b`

which gives

`\begin{gathered} 2=-15+b \\ 2+15=b \\ 17=b \end{gathered}`

Therefore, the parallel lines is given by

`y=-5x+17`