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The width of a rectangle is 6x + 8 and the length of the rectangle is 12x + 16 determine the ratio of the width to the perimeter.Supply the following:Perimeter = 21 + 2w = Ratio= w/p Final answer in simplest form:

User Neil Foley
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Solution:

For this case we know that the width is given by:

w = 6x +8

The lenght is given by:

l= 12x +16

And the perimeter would be given by:

P= 2l +2w = 2(12x+16)+ 2(6x+8)= 24x+32 +12x+16=36x + 48

And then the ratio would be:


\text{ratio}=(6x+8)/(36x+48)=(3x+4)/(18x+24)

User Gramero
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