We know that
• The volume of one ball is 221 cubic centimeters.
Since the ball is spherical, we can find its radius with the following formula.
![\begin{gathered} V=(4)/(3)\pi r^3 \\ 221\cdot(3)/(4\pi)=r^3 \\ r^3=(663)/(4\pi) \\ r=\sqrt[3]{(663)/(4\pi)}\approx3.75 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/d9z7ha0qei0583may00tcv9o1hx0ok6vv5.png)
The diameter would be double than the radius, by definition.

Since there are three balls in the cylinder, the height would be

Now, we find the volume of the cylindrical package.

Therefore, the volume of the cylindrical package is 993.52, approximately.