Answer:
a) Time taken to hit the ground = 1.674 seconds
b) Height at 1 second = 12 m
Step-by-step explanation:
The equation representing the height of the water balloon after t seconds is:
![h(t)=-16t^2+25t+3](https://img.qammunity.org/2023/formulas/mathematics/college/1poelgjkcjdc960dn63xxc8wkav8vawauv.png)
a) At the ground, h(t) = 0
![\begin{gathered} 0=-16t^2+25t+3 \\ \\ 16t^2-25t-3=0 \\ \\ Using\text{ the quadratic formula} \\ t=(-(-25)\pm√((-25)^2-4(16)(-3)))/(2(16)) \\ \\ t=(25\pm√(817))/(32) \\ \\ t=-0.111975,\text{ 1.67448} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/946t1207vuqas8slmnqkz2p4kodtjwytzf.png)
Since time cannot be negative:
Time taken to hit the ground = 1.674 seconds
b) Height at t = 1 second
![\begin{gathered} H(t)=-16t^2+25t+3 \\ \\ H(1)=-16(1^2)+25(1)+3 \\ \\ H(1)=-16+25+3 \\ \\ H(1)=12\text{ m} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/n2fd86l77hkxjuk5zsumjwyfo31c24ux8m.png)
Height at 1 second = 12 m