Question

Finding a final amount in a word problem on exponential growth or decay

Answer 1

19g

Step-by-step explanation:

Given the starting amount as 155grams, the below amount will be left after the 1st half life;

`(155g)/(2)=77.5g`

After the 2nd half-life, the below amount will remain;

`(77.5g)/(2)=38.75g`

After the 3rd half-life, the below amount will remain;

`\begin{gathered} (38.75)/(2)=19.375g\approx19g\text{ (rounding to the nearest gram)} \\ \end{gathered}`