Question

Find the value of z that makes quadrilateral EFGH a parallelogram.2zz+10FEHGz=Submit

Answer 1

In a parallelogram opposite sides have the same length therefore, for figure EFGH to be a parallelogram we must have that:

`GF=HE`

Substituting we get:

`z+10=2z`

Now, we solve for "z". First, we subtract "z" from both sides:

`\begin{gathered} z-z+10=2z-z \\ 10=z \end{gathered}`

Therefore, the value of "z" is 10.